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Pisicatha574
a fost răspuns

Efectuari si apoi simplificati fractiile ordinare obtinute:
a)1supra6+2supra6
b)5supra12+1supra12
c)5supra18+5supra18
d)5supra27+13supra27
e)13supra10+7supra10
f)4supra21+24supra21

Ajutorrrrrr

Răspuns :

Nitugheorghe57
1/6+3/6=4/6 se simplifica prin 2=2/3
5/12+1/12=6/12 se simplifica prin2=3/6 prin3=1/2
5/18+5/18=10/18 se simplifica prin 2=5/9
5/27+13/27=18/27 se simplifica prin 3=6/9⇒prin3=2/3
13/10+7/10=20/10⇒se simplifica prin10=2
4/21+24/21=28/21⇒se simplifica prin7⇒4/3
sucees
Rontzica
a)1/6+2/6=3/6(simplificam prin 3)=1/2;
b)5/12+1/12=6/12(simplificam prin 6)=1/2;
c)5/18+518=10/18(simplificam prin 2)=5/9;
d)5/27+13/27=18/27(simplificam prin 9)=2/3;
e)13/10+7/10=20/10(simplificam prin 10)=2/1=2;
f)4/21+24/21=28/21(simplificam prin 7)=4/3;
"/=>supra"

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