a/3=b/5 a=3b/5
(a-5)/(b+2)=(a+b)/(19b+2)
(3b/5-5)/b+2)=(3b/5+b)/(19b+2)
[(3b-25)/5]/(b+2)=[(3b+5b)/5]/(19b+2)
(3b-25)/(b+2)=8b/(19b+2)
(3b-25)(19b+2)=8b(b+2)
57b²-475+6b-50=8b²+16b
49b²-485-50=0
49b²+5b-490b-50=0
b(49b+5)-10(49b+5)=0
(49b+5)(b-10)=0
49b+5=0 b=-5/49 a=3*(-5/49)/5=-3/49
b-10=0 b=10 a=3*10/5=30/5=6
