fie abc si mnp doua triunghiuri cu m(A)=90*=m(M).Daca:
a)BC=NP=10cm,AB=MN=7cmsi perimetrul ABC=23cm,aflati MP
b)BC=NP=11cm,AC=MP=9cm si perimetrul MNP=27cm, aflati AB
c)BC=NP=13cm , AB=8cm,MP=10cm si perimetrul MNP=31cm,artati ca ABC=MNP
d)BC=NP=14 cm , AC=7 cm , MN=12 cm si perimentrul MNP=33 cm,aratati ca ABD=MNP.