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Otaku007
a fost răspuns

(x-2)(x+2)(x²+4)-(x²+1)²+2(x+1)²=

Răspuns :

Nitugheorghe57
(x-2)(x+2)(x²+4)-(x²+1)²+2(x+1)²=
x²+2x-2x-4)(x²+4)-(x∧4+2x²+1²)+2(x²+2x+1²)=
(x²-4)(x²+4)-(x∧4+2x²+1)+2x²+4x+2=
(x∧4+4x²-4x²-16)-x∧4-2x²-1+2x²+4x+2=
x∧4+4x²-16-x∧4-2x²-1+2x²+4x+2=
4x²+4x-15

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