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determina valorile lui a din egalitatile:238-173-7×7=2×a;;(5×10+10×5+9:3)-63=5×a;;369-208-(10×10+5)=7×a

Răspuns :

Coco0987
238-173-7×7=2×a
238-173-49=2xa
16=2xa
a=16:2
a=8

(5×10+10×5+9:3)-63=5×a
(50+50+3)-63=5xa
103-63=5xa
40=5xa
a=40:5
a=8

369-208-(10×10+5)=7×a
161-(100+5)=7xa
161-105=7xa
56=7xa
a=56:7
a=8

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