Răspuns :
a/7=5/3⇒ a=35/3; rezolvam mai intai 35/3+7/1 dand numitor comun pe 3 =56/3 totul supra 7,se simplifica 56 cu 7 si ramane 8/3=18,(6). Sper ca te-am ajutat!
[tex] \frac{a}{7} = \frac{5}{3} [/tex] => a = [tex] \frac{7 X 5}{3} [/tex] = [tex] \frac{35}{3} [/tex]
a + [tex] \frac{7}{7} [/tex] = [tex] \frac{35}{3} [/tex] + [tex] \frac{7}{7} [/tex] =
[tex] \frac{35}{3} [/tex] amplificam cu 7 = [tex] \frac{35 X 7}{3 X 7} [/tex] = [tex] \frac{245}{21} [/tex]
[tex] \frac{7}{7} [/tex] amplificam cu 3 = [tex] \frac{7 X 3}{7 X 3} [/tex] = [tex] \frac{21}{21} [/tex]
[tex] \frac{245}{21} + \frac{21}{21} [/tex] = [tex] \frac{245 + 21}{21} [/tex] = [tex] \frac{266}{21} [/tex] = [tex] \frac{38}{3} [/tex] pentru ca am simplificat cu 7, iar [tex] \frac{38}{3} [/tex] = 12,(6)
a + [tex] \frac{7}{7} [/tex] = [tex] \frac{35}{3} [/tex] + [tex] \frac{7}{7} [/tex] =
[tex] \frac{35}{3} [/tex] amplificam cu 7 = [tex] \frac{35 X 7}{3 X 7} [/tex] = [tex] \frac{245}{21} [/tex]
[tex] \frac{7}{7} [/tex] amplificam cu 3 = [tex] \frac{7 X 3}{7 X 3} [/tex] = [tex] \frac{21}{21} [/tex]
[tex] \frac{245}{21} + \frac{21}{21} [/tex] = [tex] \frac{245 + 21}{21} [/tex] = [tex] \frac{266}{21} [/tex] = [tex] \frac{38}{3} [/tex] pentru ca am simplificat cu 7, iar [tex] \frac{38}{3} [/tex] = 12,(6)