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aflati x stiind ca xa+xb+xc=40 si a+b+c=10; 4ax+3bx-2cx=80 si 4a+3b=2c+16

Răspuns :

CarMina03
xa+xb+xc=40 si a+b+c=10


xa+xb+xc=40
x(a+b+c)=40
x*10=40
x=40/10
x=4


4ax+3bx-2cx=80 si 4a+3b=2c+16

x(4a+3b-2c)=80
x(2c+16-2c)=80
x*16=80
x=80/16
x=5


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