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Jumpforjoy
a fost răspuns

[tex]a) \frac{x-1}{2} + \frac{x+2}{4} + \frac{1}{3} = \frac{x+5}{8} +1 \frac{7}{12} \\\\
b) \frac{x+1}{2} + \frac{2x+6}{3} = \frac{3x+21}{5} [/tex]

Răspuns :

Renatemambouko
(x-1)/2 + (x+2)/4+1/3 = (x+5)/8+1 7/12
(x-1)/2 + (x+2)/4 = (x+5)/8+19/12-1/3 
12x-12 + 6x+12 = 3x+15+38-8
18x = 3x+45
15x=45
x=3

(x+1)/2 + (2x+6)/3 = (3x+21)/5
15x+15+20x+60=18x+126
35x+75=18x+126
17x=51
x=3

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