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a fost răspuns

Calculati : 3 + 7 + 11 + 15 +  . . . + 2002  ( Prin metoda lui GAUSS )

Răspuns :

suma lui gauss
4x1-1+4x2-1+4x3-1+4x4-1+.......+4x500-1+2002
4(1+2+3+4+....+4x500)-500+2002=
4x501x500/2-500+2002=
2004x250-500+2002
3+7+11+15+....2002=(1+2)+(3+4)+(5+6)+(7+8)+.....+(1000+1001)+2002
formula pt suma n(n+1):2
⇒2002(2002+1):2=1001*2003=2005003