M= (23gNa+14gN+3x16gO)/mol= 85g/mol NaNO3
M= (1gH+14gN+3x16gO)/mol= 63g/mol HNO3
-Calculez masa de substanta pura din slapetru
p/100= m,pur/m,impur---> 95/100= m,pur/179=> m,pur= 170,05kg pur
-ecuatia reactiei
2mol 2mol
H2SO4 +2 NaNO3----> Na2SO4+2HNO3
2x85kg..........................2x63kg
170,05kg ...........................m= calculeaza !!!