[tex]\sqrt{1,(7)} = \sqrt{1\dfrac{7}{9}} =\sqrt{\dfrac{16}{9}} = \dfrac{4}{3}
[/tex]
Exercitiul devine:
[tex]\dfrac{1}{\dfrac{4}{3}} - \dfrac{1}{2} +\dfrac{3}{4} = \dfrac{3}{4} - \dfrac{1}{2} +\dfrac{3}{4} = \dfrac{3}{4} - \dfrac{2}{4} +\dfrac{3}{4} = \dfrac{4}{4} =1[/tex]
