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a fost răspuns

Calculati:
d) [tex] \frac{1}{8}+ \frac{1}{2}*(2x-1)=2x- \frac{1}{8}*(8x-1)- \frac{1}{4}*(4x-2)[/tex]

Răspuns :

[tex] \frac{1}{8} +x- \frac{1}{2} =2x-x+ \frac{1}{8} -x+ \frac{1}{2} \\ x-2x+x+x= \frac{1}{8} + \frac{1}{2} - \frac{1}{8} + \frac{1}{2} =\ \textgreater \ x=1[/tex]

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