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Didi110
a fost răspuns

rezolvati ecuațiile a) x+3*x+5*x+...+2011*x=2*x+4*x+6*x+...+2010*x+2012 B)x+(x+1)+(x +2)+(x +3)+(x +4)=5la puterea 1995 x. x+2. x+4 C) 5. +5. +5. =3255

Răspuns :

Ioa11111
x(1+3+5+...+2011)= 2x(1+2+3+...+1006);
x ( 2-1 + 4-1 +6-1+...+2012-1)= 2X × (1006 × 1007)/ 2;
x ( 2 +4+6+...+2012 - 2011) = X ×1006×1007;
x * 1006 *1007 - 2011 x= 1006*1007x;
-2011 x=0
x=0

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