niu= 396g/44g/mol= 9moli CO2 M,co2=44g/mol
a) pV= niuRT--> px90=9x0,082x(22+273)---------------------> p=
b) 1x90= niux0,082x295--> niu=3,72mol
masa scoasa= (9-3,72)molx44g/mol---------------------------->m=
c) V= 9molx22,4l/mol-----------------------------------------------> V =
d) px90= 39x0,082x(12+273)---------------------------------------->p=