Răspuns :
AB+AC+BC=26
BC+AC=20
Scadem cele doua relatii si obtinem:
AB=6
BC=2*AC/3
2*AC/3+AC=20
5AC=60
AC=12
BC=20-12=8
AB=6; AC=12; BC=8
BC+AC=20
Scadem cele doua relatii si obtinem:
AB=6
BC=2*AC/3
2*AC/3+AC=20
5AC=60
AC=12
BC=20-12=8
AB=6; AC=12; BC=8
P ABC=26 cm P ABC=26 cm
_BC_ = _2_ AB+ AC+ BC= 26
AC 3 _BC_ = _2_ ⇒ 3BC= 2AC
BC+ AC= 20 cm AC 3 BC= _2AC_
_________________ 3
AC= ? cm
BC= ? cm AB+ AC+ BC= 26
AB= ? cm AB+ 20 =26
AB =26- 20
AB = 6 cm
AC+ BC=20 AC+BC= 20
AC+_2AC_ = 20 4 cm +BC=20
3 BC= 20- 4
3AC+2AC=20 BC= 16 cm
5AC= 20I:5
AC= 4 cm
_BC_ = _2_ AB+ AC+ BC= 26
AC 3 _BC_ = _2_ ⇒ 3BC= 2AC
BC+ AC= 20 cm AC 3 BC= _2AC_
_________________ 3
AC= ? cm
BC= ? cm AB+ AC+ BC= 26
AB= ? cm AB+ 20 =26
AB =26- 20
AB = 6 cm
AC+ BC=20 AC+BC= 20
AC+_2AC_ = 20 4 cm +BC=20
3 BC= 20- 4
3AC+2AC=20 BC= 16 cm
5AC= 20I:5
AC= 4 cm