Răspuns :
4a²+b²-4a+10b+26=0
⇔4a²-4a+1+b²+10b+5²=0
⇔(2a-1)²+(b+5)²=0
⇒2a-1=0⇔2a=1⇒a=1/2
⇒b+5=0⇒b=0-5⇒b=-5
⇔4a²-4a+1+b²+10b+5²=0
⇔(2a-1)²+(b+5)²=0
⇒2a-1=0⇔2a=1⇒a=1/2
⇒b+5=0⇒b=0-5⇒b=-5
4[tex]4a ^{2} + b ^{2} -4a+10b+26 =(2a) ^{2} -4a+1+b ^{2} +10b+25 ;
[/tex]
[tex](2a-1) ^{2} +(b+5) ^{2} =0[/tex]
deci 2a-1=0⇒2a=1⇒a=1/2
b+5=0⇒b=-5
[tex](2a-1) ^{2} +(b+5) ^{2} =0[/tex]
deci 2a-1=0⇒2a=1⇒a=1/2
b+5=0⇒b=-5