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a fost răspuns

Ajutor la două Ex va rog frumos (c-104+2)×5+3=98, 11-(7×5-9×9÷f÷3)÷8=7

Răspuns :

(c-104+2)x5+3=98
(c-104+2)x5=98-3
c-104+2=95:5
c-104=19-2
c=17+104
c=121
11-(7x5-9x9:f:3):8=7
11-(35-81:f:3):8=7
(35-81:f:3):8=11-7
35-81:f:3=4x8
81:f:3=35-32
81:f=3x3
f=81:9
f=9

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