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a fost răspuns

Simplificati fractia:
abc+bca+cab
xyz+yzx+zxy

Răspuns :

abc+bca+cab supra xyz+yzx+zxy

abc+bca+cab=
=100a+10b+c+100b+10c+a+100c+10a+b=
=111a+111b+111c=
=111(a+b+c)

xyz+yzx+zxy=
=100x+10y+z+100y+10z+x+100z+10x+y=
=111x+111y+111z=
=111(x+y+z)

111(a+b+c) supra 111(x+y+z) simplificat cu 111=a+b+c supra x+y+z

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