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Ghitavancea
a fost răspuns

 stiind ca x+y+13=24 determinati 19+2y+2x sau x+3+y+4+z+5=12 determinati 2012+x+y+z

Răspuns :

Dulibaruben
x+y+13=24
x+y=24-13
x+y=11

19+2y+2x
=19+2(y+x)
=19+2(x+y)
=19+2·11
=19+22
=41

x+3+y+4+z+5=12
x+y+z+12=12
x+y+z=12-12
x+y+z=0

2012+x+y+z
=2012+(x+y+z)
=2012+0
=2012

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