Răspuns :
a nuci in cos
a/3 nuci a luat primul, au ramas a-a/3=2a/3 nuci
1/3x2a/3=2a/9 a luat al doilea nepot, au ramas 2a/3-2a/9=4a/9 nuci
1/3x4a/9=4a/27 nuci a luat al treilea nepot, au ramas 4a/9-4a/27=8a/27 nuci
8a/27=40, a=27x40/8=135 nuci a adus bunica
a/3 nuci a luat primul, au ramas a-a/3=2a/3 nuci
1/3x2a/3=2a/9 a luat al doilea nepot, au ramas 2a/3-2a/9=4a/9 nuci
1/3x4a/9=4a/27 nuci a luat al treilea nepot, au ramas 4a/9-4a/27=8a/27 nuci
8a/27=40, a=27x40/8=135 nuci a adus bunica
a=nr de nuci
[tex] \frac{a}{3} primul.copil \\ a- \frac{a}{3} = \frac{2a}{3} rest \\ \frac{2a}{3} /3= \frac{2a}{9} al.2lea.copil \\ \frac{2a}{3} - \frac{2a}{9} = \frac{6a-2a}{9} = \frac{4a}{9} rest \\ \frac{4a}{9} /3= \frac{4a}{27} al3lea.copil \\ \frac{a}{3} + \frac{2a}{9} + \frac{4a}{27} +40=a \\ 9a+6a+4a+1080=27a \\ 8a=1080 \\ a=1080:8 \\ a=135 nuci.a.adus.bunica[/tex]
[tex] \frac{a}{3} primul.copil \\ a- \frac{a}{3} = \frac{2a}{3} rest \\ \frac{2a}{3} /3= \frac{2a}{9} al.2lea.copil \\ \frac{2a}{3} - \frac{2a}{9} = \frac{6a-2a}{9} = \frac{4a}{9} rest \\ \frac{4a}{9} /3= \frac{4a}{27} al3lea.copil \\ \frac{a}{3} + \frac{2a}{9} + \frac{4a}{27} +40=a \\ 9a+6a+4a+1080=27a \\ 8a=1080 \\ a=1080:8 \\ a=135 nuci.a.adus.bunica[/tex]