1 dm ^3,= 1l ; V = aria bazei x inaltimea ( muchia laterala pt ca este prisma)m= lxl x m = 8x 8 x 5'= 64x 5 = 320dm ^3 ='320'litri; aria totala ='perimetrul bazei x muchia + 2 aria bazei='4l x m + 2l^2 = 4x 8x 5 + 2x 64= 160+ 128= 288m patrati; nu intrleg ce 100 de bucati ? 6) aria totala = 2 aria bazei + aria laterala = 2x abx bc+ perimetrul bazei x aa'= 2x 60x 24+ 2( 60+ 24) x 40 = 120x 24+ 2x 84x 40 = 2880+ 6780 = ; volumul = aria bazei x muchia laterala ( inaltimea)= abxbcxaa' = 60x 24x 40 = 6x 2,4x 4 = 24x 2,4= 57,6 dm^3 ='57,6 litri