Răspuns :
100a+10b+c+100b+10c+a+100c+10a+b=
111a+111b+111c=111(a+b+c)
111(a+b+c)divizibil cu :37
333:37=9
111a+111b+111c=111(a+b+c)
111(a+b+c)divizibil cu :37
333:37=9