a / 3 = b / 5 = c/ 7 = k ; k≠ 0 ; k ∈ N
a = 3k
b = 5k
c = 7k
a. a + c = 2b , adica 3k + 7k = 2 · 5 k
10k = 2 · 5k adevarat
b. ( 3k)² - ( 5k)² + ( 7k)² =297
9k² - 25k² + 49k² =297
33k² = 297 ; k² =297:33 = 9
k ∈ N atunci k = √9 = 3
a = 3·3 = 9
b = 5· 3 =15
c = 7·3 =21