a). x`1 = 1/x si x`2 = 1 / x^2, rezulta: x^2 - 3/x * (1/2 * 1/x^2) = x^2 - 2/2x^3 = (se aduce la acelasi numitor) = x^2*x^3 - 3/2x^3 = (x^5 - 3) / 2x^3 (cam avansat pt. clasa a 8-a...)
b). -x(x^2-3x+2) = -x(x^2 - x - 2x + 2) = -x [x(x-1) - 2(x-1)] = -x(x-1)(x-2)
c). √2*x^2(3√2-x) = √2*3√2*x^2 - x√2 = 6x^2 - x√2
