Răspuns :
Consideram Latimea( l)=3, Lungimea( L)=4 si inaltimea (h)=5
Nu ai decat sa aplici formulele.
At=Al+2Ab (Al=aria laterala si Ab=aria bazei)
Al=2(Lh+lh)
Ab=Ll
Al=2(20+15)=2*35=70
Ab=Ll=3*4=12
At=Al+2Ab=70+24=94 m^2
V=L*h*l=3*4*5=60 m^3
Diagonala (d) =[tex] \sqrt{ L^{2} +l^{2}+ h^{2} } [/tex] =>d=[tex] \sqrt{9+16+25}
[/tex] =>d=√50=5√2
Nu ai decat sa aplici formulele.
At=Al+2Ab (Al=aria laterala si Ab=aria bazei)
Al=2(Lh+lh)
Ab=Ll
Al=2(20+15)=2*35=70
Ab=Ll=3*4=12
At=Al+2Ab=70+24=94 m^2
V=L*h*l=3*4*5=60 m^3
Diagonala (d) =[tex] \sqrt{ L^{2} +l^{2}+ h^{2} } [/tex] =>d=[tex] \sqrt{9+16+25}
[/tex] =>d=√50=5√2