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Andreeaa419
a fost răspuns

Calculati :
[tex]a= \sqrt{(2 \sqrt{3} } -3 \sqrt{2} )^2[/tex]

si

[tex]b= \frac{9}{2 \sqrt{3} } - \sqrt{3} [/tex]

Răspuns :

[tex]a=\sqrt{(2\sqrt3-3\sqrt2)^2} = |2\sqrt3-3\sqrt2| = -2\sqrt3+3\sqrt2[/tex]

b)

[tex] ... = \dfrac{9\sqrt3}{2\cdot3}-\sqrt3=\dfrac{3\sqrt3}{2} -\dfrac{\sqrt3}{1} =\dfrac{3\sqrt3 -2\sqrt3}{2} =\dfrac{\sqrt3}{2}[/tex]

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