Zn+H2SO4=ZnSO4+H2
M H2SO4=2*1+32+4*16=98
M H2=2*1=2
Calculam masa dizolvata de acid sulfuric:
[tex]c= \dfrac{md*100}{ms} [/tex]
[tex]md= \dfrac{c*ms}{100} [/tex]
Inlocuim:
[tex]md= \dfrac{20*10}{100}=2gH2SO4 [/tex]
98 g H2SO4............2 g H2
2 g H2SO4............. x
[tex]x= \dfrac{2*2}{98}=0,04 gH2 [/tex]
In concluzie,in urma reactiei dintre zinc si 10 g de acid sulfuric de concentratie 20% se degaja 0,04 g hidrogen.
