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Erika02
a fost răspuns

[tex] \frac{1}{x-1} - \frac{2x}{1- x^{2} }- \frac{1}{x+1} [/tex]

Răspuns :

Mikkka
1/ (x-1)   -   2x/(x-1)(x+1)   - 1/(x+1) =
(x+1)/(x-1)(x+1)   -2x/(x-1)(x+1)   - (x-1)/ (x-1)(x+1) =
(x+1-2x-x+1)/ (x-1)(x+1)=
(-2x+2)/ (x-1)(x+1)=
-2 ( x-1)/(x-1)(x+1)=
-2/x+1

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