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3 intregi si 1 supra 2×√0,0225-0,(6)×√1,125×2+0,2(7)×√0,09.

Răspuns :

Renatemambouko
3 intregi si 1/2 =7/2
√0,0225=√225/10000=15/100=3/20
0,(6)=6/9=2/3
√1,125×2=√2,25=√225/100=15/10=3/2
0,2(7)=(27-2)/90=25/90=5/18
√0,09=√9/100=3/10
3 intregi si 1/2×√0,0225-0,(6)×√1,125×2+0,2(7)×√0,09 =
=7/2×3/20-2/3×3/2+5/18×3/10 =
=21/40-1+1/12=
=(63-120+10)/120=-47/120=0,391(6)







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