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a fost răspuns

Se considera expresia E(x)= ([tex] \frac{x-2}{x^{2}-4 } [/tex] * [tex] \frac{5x+10}{x-3} } [/tex] + 1 ) * [tex] \frac{x-3}{x+2} [/tex]

Răspuns :

Renatemambouko
E(x)=[(x-2)/(x²-4)×(5x+10)/(x-3)+1] ×(x-3)/(x+2) =
=[(x-2)/(x+2)(x-2)×5(x+2)/(x-3)+1] ×(x-3)/(x+2) =
=[5/(x-3)+1] ×(x-3)/(x+2) =
=(5+x-3)/(x-3) ×(x-3)/(x+2) =
=(x+2)/(x-3) ×(x-3)/(x+2) =1

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