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Katiusaunciulenco
a fost răspuns

Ajutor va rog.Simplificati fractia.
Xlaputerea3+xlaputerea2-x-1
supra la xlaputerea2+2x+1
X3+X2-X-1
X2+2X+1

Răspuns :

C04f
[tex] \frac{ x^{3}+ x^{2} -x -1}{ x^{2} +2x+1}= \frac{ x^{2}(x+1)-(x+1)}{ (x+1)^{2} } =[/tex][tex] \frac{(x+1)( x^{2} -1)}{ (x+1)^{2} } = \frac{(x+1)(x+1)(x-1)}{ (x+1)^{2} } [/tex] simplificam cu [tex]( x+1)^{2} [/tex] si obtinem fractia =x-1

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