3) 4n + 3 = 3 , n= 0; 4n + 3. = 7 rezulta 4n = 4 , n =1; 4n + 3= 11, 4n = 8, n= 2; 4n +3= 15, 4n = 12, n = 3; 4n +3= 19, 4n = 16, n =4 ; ne da conditia n=8 adevarat , y=3; pt y=2 , 4x2>= 8 adevarat B = { 2, 3, } ;a) A intersectat cu B = { 2, 3} ; b) A reunit cu B = { 0, 1, 2, 3}; c) A-B = { 0, 1} ; d) B-A = 0 - multimea vida
