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a fost răspuns


Descompuneti in factori trinomul .

X²-2X-8

4X²-3X-1

-X²+X+2

Răspuns :

[tex]x^2-2x-8=x^2-2x+1-9=(x-1)^2-3^2 \\\;\\=(x-1-3)(x-1+3)=(x-4)(x+2)[/tex]



[tex]\it4x^2-3x-1 =4x^2-4x+x-1=4x(x-1)+(x-1)= \\\;\\=(x-1)(4x+1)[/tex]




[tex]-x^2+x+2=-x^2+2x-x+2=-x(x-2)-(x-2)= \\\;\\=(x-2)(-x-1) =-(x-2)(x+1)[/tex]



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