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Idyana87
a fost răspuns

1. Efectuati:
[tex]( \frac{1}{2+ \sqrt{3} } + \frac{2}{ \sqrt{3}-1 } ) ori ( \frac{4}{3 \sqrt{2}+4 } - \frac{3}{3-2 \sqrt{2} } )[/tex]

Răspuns :

Meryistrate
rationalizam si avem
(2-√3/4-3+2(√3+1)/3-1)*(4(3√2-4)/3²*2-16-3(3+2√2)/9-8)=
2-√3+2√3+2/2)*(12√3-16/2-9-6√2)=
2-√3+√3+2)*(6√3-16-9-6√2)=
4*(6√3-25-6√2)=
24√3-24√2-100=24(√3-√2)-100
sper ca nu am gresit la calcul

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