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Uden
a fost răspuns

Dau coroana
Se considera expresia :
E(x) = [tex]( x^{}-1- [/tex]- [tex] \frac{ x^{2} -1}{x+2} [/tex]) :[tex] \frac{x-1}{x+2} [/tex]

Răspuns :

Mikkka
E(x) =[ (x-1)(x+2) - (x²-1)]/ (x+2) * (x+2)/(x-1)
E(x) = (x²+2x-x-2-x²+1)/(x+2) * (x+2)/(x-1)
E(x) = (x-1)/(x+2) * (x+2)/(x-1)
E(x) = 1

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