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Stanciuoana24
a fost răspuns

1X2+2X3+3X4+.....+2013X2014 supra 2X2+4X6+6X8+...+4026X4028= 1 supra x la puterea a 2a

Răspuns :

[tex] \frac{1*2+2*3+3*4+...+2013*2014}{2*2+4*6+6*8+...+4026*4028} = \frac{1*2+2*3+3*4+...+2013*2014}{2(1*2+2*3+3*4+...+2013*2014)} = \frac{1}{2} [/tex]
[tex] \frac{1}{2} = \frac{1}{ x^{2} } => x^{2} =2=>x= \sqrt{2} [/tex]

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