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MariaElena44
a fost răspuns

Calculati media arutmetica a numereleor:
3 si 11 ; 4 si 56 ; 202 si 34 ; 0 si 38 ; 31 si 53 ;2011 si 2009 ; 447 si 333 ; 2011 si 1.
Va dau coronita daca ma ajutati.Mersii

Răspuns :

Pisy1998
3+11/2=14/2=7
4+56/2=60/2=30
202+34/2=236/2=118
0+38/2=19
31+53/2=42
2011+2009/2=4020/2=2003
447+333/2=780/2=390
2011+1/2=2012/2=1006
Ghicitoare5
(3+11):2=7 (4+56):2=30 (202+34):2=118 (0+38):2=19 (31+53):2=42 (2011+2009):2=2010 (447+333):2=390 (2011+1):2=1006

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