3mol 2mol M,FeCl3= (56gFe+3x35,5gCl)/mol
2Fe +3Cl2= 2FeCl3
-calculez nr.mol clorura: niu=m/M-->niu= 32,5g/162,5gmol=0,2molFeCl3
-calculez nr.moli Cl2: 2mol Fe Cl3.......3mol Cl2
0,2mol.................niu=0,3mol Cl2
-calculez volumul, din ecuatia de stare:
pV= niu X RT 87o/760xV= 0,3X0,082X290---> CALCULEAZA V in litri, apoi in cm cub( 1at=760mmHg)