Vom folosi numarul lui Avogaro,mai exact:6,023*10²³
Acum rezolvam:[tex]1molCa=6,023*10^2^3\\
0,5moliCa=x\\
=\ \textgreater \ x= 6,023*10^2^3*0,5\\
=\ \textgreater \ x=3,0115*10^2^3atomi.\\\\
1molN=6,023*10^2^3\\
0,5moliN=x\\
=\ \textgreater \ x=6,023*10^2^3*0,5\\
=\ \textgreater \ x=3,0115*10^2^3atomi\\\\
1molO=6,023*10^2^3\\
0,5moliO=x\\
=\ \textgreater \ x=6,023*10^2^3*0,5\\
=\ \textgreater \ x=3,0115*10^2^3atomi
[/tex]
