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Cum rezolv : lim x -> 3 din x la 2 - 1 / x la 2 - 6x - 9?

Răspuns :

Matepentrutoti
[tex] \lim_{x \to 3} \frac{x^2-1}{x^2-6x-9} =\frac{3^2-1}{3^2-6*3-9} = \frac{8}{-18} =- \frac{4}{9} [/tex]
[tex]\displaystyle \lim_{x \to 3} \frac{x^2-1}{x^2-6x-9} = \frac{3^2-1}{3^2-6 \cdot 3-9} = \frac{9-1}{9-18-9} = \frac{8}{-9-9} =- \frac{8}{18} ^{(2} =- \frac{4}{9} [/tex]