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E(x)=(x-2008)[tex] ^{2009} [/tex] + (2008-x)[tex] ^{2009} [/tex]

Răspuns :

Deni00
Notam : t = x - 2008
-t = -x + 2008 => -t = 2008-x
E(x) devine:
[tex]E(x)=t^{2009}+(-t)^{2009}=t^{2009}-t^{2009}=\ \textgreater \ E(x)=0[/tex]