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Neacsugeorged
a fost răspuns

x=[tex] \sqrt{300} [/tex]+2[tex] \sqrt{192} [/tex]-3[tex] \sqrt{675} [/tex]-[tex] \sqrt{108[/tex]
y=[tex] \sqrt{432[/tex]+2[tex] \sqrt{588[/tex]-3[tex] \sqrt{1200[/tex]+15[tex] \sqrt{12[/tex]

Răspuns :

[tex]x=\sqrt{300}+2\sqrt{192}-3\sqrt{675}-\sqrt{108}\\ x=10\sqrt{3}+2*8\sqrt3-3*15\sqrt3-6\sqrt3\\ x=10\sqrt3+16\sqrt3-45\sqrt3-6\sqrt3\\ x=26\sqrt3-51\sqrt3\\ x=-25\sqrt3\\ y=\sqrt{432}+2\sqrt{588}-3\sqrt{1200}+15\sqrt{12}\\ y=12\sqrt3+2*14\sqrt3-3*20\sqrt3+15*2\sqrt3\\ y=12\sqrt3+28\sqrt3-60\sqrt3+30\sqrt3\\ y=40\sqrt3-30\sqrt3\\ y=10\sqrt3[/tex]

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