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A)Stind ca x+y+z+12=determinatix+y+z
B)Stind ca 2x+3y+44-z=68 determinati 2x-z+3y
C)Stind ca 5x+35+2z=59,determinati 5x+2z+18
D)Stind ca x+2y+21=73,determinati8y+4x+33
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Răspuns :

Mikkka
b) 2x+3y-z=68-44
2x+3y-z=24

c) 5x+2z=59-35
5x+2z=24 /+18
5x+2z+18=42

d) x+2y=73-21
x+2y=52/ *4
4x+8y=208/+33
8y+4x+33= 241

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