Răspuns :
2^(2×)+4^(×+1)=80
2^(2×)+[2^2]^(×+1)=80
2^(2×)+2^(2×+2)=80
[2^(2×)](1+2^2)=80
2^(2×)=80÷5=16=2^4
2×=4
×=2
2^(2×)+[2^2]^(×+1)=80
2^(2×)+2^(2×+2)=80
[2^(2×)](1+2^2)=80
2^(2×)=80÷5=16=2^4
2×=4
×=2
2 la puterea(2x+4)(x+1)=80
2 la puterea 2x la a doua +6x +4=80
faci delta =B la patrat -4 ori a ori c=36-32=4
dupa faci x1,2=-b +sau- radical din delta/2a=-6 plus sau - 2/4= x1=-6 +4/4=-2/4
x2=-6-4/4=-10/4
2 la puterea 2x la a doua +6x +4=80
faci delta =B la patrat -4 ori a ori c=36-32=4
dupa faci x1,2=-b +sau- radical din delta/2a=-6 plus sau - 2/4= x1=-6 +4/4=-2/4
x2=-6-4/4=-10/4