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1.Numerele 1277 si 411 impartite la acelasi numar natural diferit de zero,dau resturile 17 si respective 15.Aflati numarul.

Răspuns :

Cmccmc49
1277:x=C1⇒1277=x*C1+17
411:x=C2⇒411=x*C2+15

1277-17=x*C1⇒1260=x*C1
 411-15=x*C2⇒396=x*C2

calculam(1260,396):
1260=2² * 3² * 5 *7
396=2² * 3² * 11
⇒(1260,396)=2² * 3²=36

 x=36

D36:{1,2,3,4,6,9,12,18,36}
x>15,x>17⇒x=18,36

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