Răspuns :
fie nr a si b, a-primul numar b-al doilea nr
a+b=25
1/4*a -1/3*b=1 => 3*a-4*b=12 =>3*a=12+4b=> a=4+4/3*b
dar a+b=25=> 4+4/3*b +b =25=>4*b+3*b=21*3 =>7*b=21*3=>b=9 => a=16
a+b=25
1/4*a -1/3*b=1 => 3*a-4*b=12 =>3*a=12+4b=> a=4+4/3*b
dar a+b=25=> 4+4/3*b +b =25=>4*b+3*b=21*3 =>7*b=21*3=>b=9 => a=16
a+b=25
a/4-b/3=1
3a-4b =12
3a=12+4b
a=(12+4b)/3
(12+4b)/3+b=25
12+4b+3b=25
7b=75-12
b=63/7
b=9
a=25-9
a=16
v: 9+16=25
multa bafta