Răspuns :
a+a+2+a+4+a+6=432
4a=432-12
a=420:4
a=105
105+2=107
105+4=109
105+6=111
nr sunt consecutive impare 105,107,109,111
4a=432-12
a=420:4
a=105
105+2=107
105+4=109
105+6=111
nr sunt consecutive impare 105,107,109,111