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ECUATIA
[tex] \frac{3}{4} [ \frac{3}{4} + \frac{3}{4} ( \frac{4}{3} x+ \frac{1}{3} )]=3 [/tex]

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Răspuns :

Renatemambouko
3/4[3/4+3/4(4x/3+1/3)]=3
[3/4+3/4(4x/3+1/3)]=3:3/4
[3/4+3/4(4x/3+1/3)]=3 ×4/3
3/4+3/4(4x/3+1/3)=4
3/4(4x/3+1/3)=4-3/4
3/4(4x/3+1/3)=13/4
4x/3+1/3=13/4 :3/4
4x/3+1/3=13/4 ×4/3
4x/3+1/3=13/3
4x/3=13/3-1/3
4x/3=12/3
4x/3=4
4x=12
x=3