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Darius1974
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4+8+12+........+396=200x
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Marymovileanu
4·(1+2+3+...+99) = 200x.
[tex] \frac{4*(99*100)}{2} [/tex] = 2·(99·100).
2·99·100=200x.
99·200=200x.
99·200:200=x.
99=x.
x=99.
4·(1+2+3+...+99) = 200x. \frac{4*(99*100)}{2} = 2·(99·100). 2·99·100=200x. 99·200=200x. 99·200:200=x. 99=x. x=99.