Răspuns :
z₁+ z₂+ z₃= d km z₁+ z₂+ z₃= d km
________________ 20% din d + 30 % din r₁+560= d
z₁= 20% din d _20 d_ + _30 r₁_ +560 = d
z₂= 30 % din r₁ 100 100
z₃= 560 km _2d_ + _3r₁_ +560 = d
10 10
2d+ 3r₁+ 5 600= 10d
3r₁+ 5 600= 10d- 2d
3r₁+ 5 600= 8d
r₁= d- _20d_ 3( d- _20d_)+ 5 600= 8d
100 100
3( d- _2d_) + 5 600= 8d
10
3(_10d- 2d_) + 5 600 = 8d
10d
3· 8d+ 56 000?=8 ·10d
24d+ 56 000= 80d
56 000= 80d- 24d
56 000= 56d I : 56
1 000= d
________________ 20% din d + 30 % din r₁+560= d
z₁= 20% din d _20 d_ + _30 r₁_ +560 = d
z₂= 30 % din r₁ 100 100
z₃= 560 km _2d_ + _3r₁_ +560 = d
10 10
2d+ 3r₁+ 5 600= 10d
3r₁+ 5 600= 10d- 2d
3r₁+ 5 600= 8d
r₁= d- _20d_ 3( d- _20d_)+ 5 600= 8d
100 100
3( d- _2d_) + 5 600= 8d
10
3(_10d- 2d_) + 5 600 = 8d
10d
3· 8d+ 56 000?=8 ·10d
24d+ 56 000= 80d
56 000= 80d- 24d
56 000= 56d I : 56
1 000= d
notăm cu x drumul
Prima zi : [tex]x- \frac{20x}{100}=A[/tex] (A este restul pe care il are de parcurs in urmatoarele zile)
A doua zi : [tex]A- \frac{30A}{100}=B [/tex] (B reprezinta drumul pe care il are de parcurs in a treia zi)
A treia zi : B=560
[tex]A- \frac{30A}{100}=560 [/tex]
[tex]100A-30A=56000[/tex]
[tex]70A=56 000[/tex]
[tex]A= \frac{56000}{70}=800 [/tex]
[tex]x- \frac{20x}{100}=A [/tex]
[tex]x- \frac{20x}{100}=800[/tex]
[tex]100x-20x=80000 80x=80000[/tex]
[tex]x= \frac{80000}{80} = \frac{8000}{8}=1000 km [/tex]
Prima zi : [tex]x- \frac{20x}{100}=A[/tex] (A este restul pe care il are de parcurs in urmatoarele zile)
A doua zi : [tex]A- \frac{30A}{100}=B [/tex] (B reprezinta drumul pe care il are de parcurs in a treia zi)
A treia zi : B=560
[tex]A- \frac{30A}{100}=560 [/tex]
[tex]100A-30A=56000[/tex]
[tex]70A=56 000[/tex]
[tex]A= \frac{56000}{70}=800 [/tex]
[tex]x- \frac{20x}{100}=A [/tex]
[tex]x- \frac{20x}{100}=800[/tex]
[tex]100x-20x=80000 80x=80000[/tex]
[tex]x= \frac{80000}{80} = \frac{8000}{8}=1000 km [/tex]
